What is area g(x)= 4/(2-x),y=4,x=0 ?

The answer to area g(x)= 4/(2-x),y=4,x=0 is 4-4ln(2)

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area g(x)= 4/(2-x),y=4,x=0

area

g (x) = \frac{4}{2 - x}, y = 4, x = 0

4 - 4 ln (2)

Decimal Notation

1.22741 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 4 - \frac{4}{2 - x} d x

Solve

\int_{0}^{1} 4 - \frac{4}{2 - x} d x : 4 - 4 ln (2)

The area is:

= 4 - 4 ln (2)

\frac{\partial}{\partial x} (x + y^{4})

\frac{d}{d x} ((2 x^{3} + 3 x - 1)^{4})

\frac{\partial}{\partial x} (3 x^{3} y^{3} - 2 x^{2} + 3 y + 40)

2 - \frac{4}{t}

\int \frac{ln ( 13 x )}{x} d x

What is area g(x)= 4/(2-x),y=4,x=0 ?
The answer to area g(x)= 4/(2-x),y=4,x=0 is 4-4ln(2)