What is the solution for y^{''}+6y^'+9y=3e^{-3t} ?

The solution for y^{''}+6y^'+9y=3e^{-3t} is y=c_{1}e^{-3t}+c_{2}te^{-3t}+(3e^{-3t}t^2)/2

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y^{''}+6y^'+9y=3e^{-3t}

y^{^{''}} + 6 y^{^{'}} + 9 y = 3 e^{- 3 t}

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t} + \frac{3 e ^{- 3 t} t ^{2}}{2}

Solution steps

y^{''} (t) + 6 y^{'} (t) + 9 y = 3 e^{- 3 t}

Solve linear ODE:

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t} + \frac{3 e ^{- 3 t} t ^{2}}{2}

y = c_{1} e^{- 3 t} + c_{2} t e^{- 3 t} + \frac{3 e ^{- 3 t} t ^{2}}{2}

\frac{d y}{d x} + \frac{y}{x} = 1

f (x) = arcsin (\frac{5}{x ^{2}})

x \to 2 lim (3 π)

\frac{1}{s \cdot ( s + 1 )}

(t)^{^{'}}

What is the solution for y^{''}+6y^'+9y=3e^{-3t} ?
The solution for y^{''}+6y^'+9y=3e^{-3t} is y=c_{1}e^{-3t}+c_{2}te^{-3t}+(3e^{-3t}t^2)/2