What is (\partial)/(\partial x)(sin(2x+3y)) ?

The answer to (\partial)/(\partial x)(sin(2x+3y)) is cos(2x+3y)*2

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(\partial)/(\partial x)(sin(2x+3y))

\frac{\partial}{\partial x} (sin (2 x + 3 y))

cos (2 x + 3 y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x + 3 y))

Treat

y

as a constant

Apply the chain rule:

cos (2 x + 3 y) \frac{\partial}{\partial x} (2 x + 3 y)

= cos (2 x + 3 y) \frac{\partial}{\partial x} (2 x + 3 y)

\frac{\partial}{\partial x} (2 x + 3 y) = 2

= cos (2 x + 3 y) \cdot 2

y = 7 x - x^{2}

\int_{- 1}^{1} \frac{10}{x ^{2}} d x

\int_{3}^{12} (6 x + 1) d x

\int (\frac{1}{x ^{10}} - x^{10} - \frac{1}{3}) d x

4 t^{3} cos (t)

What is (\partial)/(\partial x)(sin(2x+3y)) ?
The answer to (\partial)/(\partial x)(sin(2x+3y)) is cos(2x+3y)*2