What is the limit as x approaches infinity of 4^x-1 ?

The limit as x approaches infinity of 4^x-1 is infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches infinity of 4^x-1

x \to \infty lim (4^{x} - 1)

\infty

Solution steps

x \to \infty lim (4^{x} - 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (4^{x}) - x \to \infty lim (1)

x \to \infty lim (4^{x}) = \infty

x \to \infty lim (1) = 1

= \infty - 1

Apply Infinity Property:

\infty - c = \infty

= \infty

x \to 3 lim (\frac{( x ^{2} - 9 )}{2 x - 6})

x \to \infty lim (\frac{2 ^{x}}{3 ^{x - 1}})

\int 2 - x d x

\frac{d}{d x} (cos (\frac{π}{2} x))

\int_{- π}^{0} x d x

What is the limit as x approaches infinity of 4^x-1 ?
The limit as x approaches infinity of 4^x-1 is infinity