What is the derivative of f(x)=(x^2)/(9+8x) ?

The derivative of f(x)=(x^2)/(9+8x) is (18x+8x^2)/((9+8x)^2)

What is the first derivative of f(x)=(x^2)/(9+8x) ?

The first derivative of f(x)=(x^2)/(9+8x) is (18x+8x^2)/((9+8x)^2)

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derivative of

f (x) = \frac{x ^{2}}{9 + 8 x}

\frac{18 x + 8 x ^{2}}{( 9 + 8 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{9 + 8 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 9 + 8 x ) - \frac{d}{d x} ( 9 + 8 x ) x ^{2}}{( 9 + 8 x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9 + 8 x) = 8

= \frac{2 x ( 9 + 8 x ) - 8 x ^{2}}{( 9 + 8 x ) ^{2}}

Expand

2 x (9 + 8 x) - 8 x^{2} : 18 x + 8 x^{2}

= \frac{18 x + 8 x ^{2}}{( 9 + 8 x ) ^{2}}

\int x^{5} \cdot e^{x^{3}} d x

\int \frac{x}{x ^{2} x ^{2} - 16} d x

\frac{d}{d x} (tan (5 x^{2}))

\frac{\partial}{\partial x} (4 ln (x))

\frac{x ^{2}}{x ^{2} - 4}

What is the derivative of f(x)=(x^2)/(9+8x) ?
The derivative of f(x)=(x^2)/(9+8x) is (18x+8x^2)/((9+8x)^2)
What is the first derivative of f(x)=(x^2)/(9+8x) ?
The first derivative of f(x)=(x^2)/(9+8x) is (18x+8x^2)/((9+8x)^2)