What is partialfraction (x^2)/(x^2-4) ?

The solution to partialfraction (x^2)/(x^2-4) is 1-1/(x+2)+1/(x-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

partialfraction (x^2)/(x^2-4)

partial fractions

\frac{x ^{2}}{x ^{2} - 4}

1 - \frac{1}{x + 2} + \frac{1}{x - 2}

Solution steps

\frac{x ^{2}}{x ^{2} - 4}

Long division

\frac{x ^{2}}{x ^{2} - 4} : 1 + \frac{4}{x ^{2} - 4}

= 1 + \frac{4}{x ^{2} - 4}

Continue partial fractions on remainder:

\frac{4}{x ^{2} - 4}

Take the partial fraction of

\frac{4}{x ^{2} - 4} : - \frac{1}{x + 2} + \frac{1}{x - 2}

1 - \frac{1}{x + 2} + \frac{1}{x - 2}

a x \cdot e^{b x}

\int (3 x^{2} - 8 x + 2) d x

\frac{3}{cos ^{2} ( 3 x + 5 )}

\frac{d}{d t} ((t + 3)^{\frac{2}{3}} (2 t^{2} - 3)^{3})

f (t) = 5 t - 9 t^{2}

What is partialfraction (x^2)/(x^2-4) ?
The solution to partialfraction (x^2)/(x^2-4) is 1-1/(x+2)+1/(x-2)