What is the derivative of (3x+8)^2 ?

The derivative of (3x+8)^2 is 6(3x+8)

What is the first derivative of (3x+8)^2 ?

The first derivative of (3x+8)^2 is 6(3x+8)

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derivative of

(3 x + 8)^{2}

6 (3 x + 8)

Solution steps

\frac{d}{d x} ((3 x + 8)^{2})

Apply the chain rule:

2 (3 x + 8) \frac{d}{d x} (3 x + 8)

= 2 (3 x + 8) \frac{d}{d x} (3 x + 8)

\frac{d}{d x} (3 x + 8) = 3

= 2 (3 x + 8) \cdot 3

Simplify

= 6 (3 x + 8)

\int cos (7 t) d t

2 x^{3} - 1

y = (1 + 2 x)^{11}, (0, 1)

\frac{( 2 s - 1 )}{s ^{2} ( s + 1 ) ^{3}}

\int (x^{5} + 8 x^{3} - 9 x^{2} + 7 x - 5) d x

What is the derivative of (3x+8)^2 ?
The derivative of (3x+8)^2 is 6(3x+8)
What is the first derivative of (3x+8)^2 ?
The first derivative of (3x+8)^2 is 6(3x+8)