What is the derivative of f(t)=(3t-2)^5 ?

The derivative of f(t)=(3t-2)^5 is 15(3t-2)^4

What is the first derivative of f(t)=(3t-2)^5 ?

The first derivative of f(t)=(3t-2)^5 is 15(3t-2)^4

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derivative of

f (t) = (3 t - 2)^{5}

15 (3 t - 2)^{4}

Solution steps

\frac{d}{d t} ((3 t - 2)^{5})

Apply the chain rule:

5 (3 t - 2)^{4} \frac{d}{d t} (3 t - 2)

= 5 (3 t - 2)^{4} \frac{d}{d t} (3 t - 2)

\frac{d}{d t} (3 t - 2) = 3

= 5 (3 t - 2)^{4} \cdot 3

Simplify

= 15 (3 t - 2)^{4}

y = x^{3}, 0 \leq x \leq 5

\frac{\partial}{\partial y} (\frac{x y}{cos ( x )})

s^{2} + 4 s + 13

\frac{\partial}{\partial z} (cos (z) w (z))

\frac{d y}{d t} = 2 (1 - y), y (0) = 0

What is the derivative of f(t)=(3t-2)^5 ?
The derivative of f(t)=(3t-2)^5 is 15(3t-2)^4
What is the first derivative of f(t)=(3t-2)^5 ?
The first derivative of f(t)=(3t-2)^5 is 15(3t-2)^4