What is the tangent of f(x)=ln(3x+4),(2,ln(10)) ?

The tangent of f(x)=ln(3x+4),(2,ln(10)) is y= 3/10 x+ln(10)-3/5

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tangent of f(x)=ln(3x+4),(2,ln(10))

tangent of

f (x) = ln (3 x + 4), (2, ln (10))

y = \frac{3}{10} x + ln (10) - \frac{3}{5}

Solution steps

Find the slope of

f (x) = ln (3 x + 4) : \frac{df ( x )}{d x} = \frac{3}{3 x + 4}

Compute the slope of

f (x) = ln (3 x + 4)

(2, ln (10)) : m = \frac{3}{10}

Find the line with slope m=

\frac{3}{10}

and passing through

(2, ln (10)) : y = \frac{3}{10} x + ln (10) - \frac{3}{5}

y = \frac{3}{10} x + ln (10) - \frac{3}{5}

- 5 cos (3 t)

f (t) = 2 t^{3} + t

\frac{\partial}{\partial x} (\frac{x y}{x + y})

f (x) = ln (6 - x^{2})

\frac{\partial}{\partial x} (x cos (y) - y sin (x))

What is the tangent of f(x)=ln(3x+4),(2,ln(10)) ?
The tangent of f(x)=ln(3x+4),(2,ln(10)) is y= 3/10 x+ln(10)-3/5