What is the domain of f(x)=sqrt(x+2)-1/(x^2-1) ?

The domain of f(x)=sqrt(x+2)-1/(x^2-1) is -2 1

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domain of f(x)=sqrt(x+2)-1/(x^2-1)

domain

f (x) = x + 2 - \frac{1}{x ^{2} - 1}

- 2 \leq x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

[- 2, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

- 2 \leq x < - 1 or - 1 < x < 1 or x > 1

f (x) = (x + 5)^{\frac{2}{3}}

y = 18 x - 17

f (x) = \frac{x + 3}{4 - x ^{2} - 9}

f (x) = \frac{x - 3}{x ^{2} - 9}

- 6 x

What is the domain of f(x)=sqrt(x+2)-1/(x^2-1) ?
The domain of f(x)=sqrt(x+2)-1/(x^2-1) is -2<= x<-1\lor-1<x<1\lor x>1