What is the range of sqrt(x^2-10) ?

The range of sqrt(x^2-10) is f(x)>= 0

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range of sqrt(x^2-10)

range

x^{2} - 10

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x^{2} - 10 : x \leq - 10 or x \geq 10

Extreme Points of

x^{2} - 10 :

Minimum

(- 10, 0),

Minimum

(10, 0)

Find the range for the interval

- \infty < x \leq - 10 : 0 \leq f (x) < \infty

Find the range for the interval

10 \leq x < \infty : 0 \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq 0 or f (x) \geq 0

f (x) \geq 0

f (x) = - a x

f (x) = \frac{1}{x} + \frac{1}{x - 3} + \frac{1}{x - 2}

y = x^{3} - 2 x^{2} - 4 x + 3

f (x) = 4 x - 12

f (x) = \frac{( x + 2 )}{( x ^{2} - x - 6 )}