What is the inflection f(x)=(x^3)/3-x^2-3x ?

The inflection f(x)=(x^3)/3-x^2-3x is (1,-11/3)

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inflection f(x)=(x^3)/3-x^2-3x

inflection points

f (x) = \frac{x ^{3}}{3} - x^{2} - 3 x

(1, - \frac{11}{3})

Solution steps

f^{''} (x) = 2 x - 2

Find intervals:

Concave Downward

: - \infty < x < 1,

Concave Upward

: 1 < x < \infty

Plug

x = 1

into

\frac{x ^{3}}{3} - x^{2} - 3 x : - \frac{11}{3}

(1, - \frac{11}{3})

f (x) = 3 sin (π x)

2 - 7 x + 3

f (x) = x^{2} - 10 x

\frac{x + 1}{x ^{2} - 1}

2 x + 4 y = 16

What is the inflection f(x)=(x^3)/3-x^2-3x ?
The inflection f(x)=(x^3)/3-x^2-3x is (1,-11/3)