What is the inflection f(x)=2-ln(x^2+1) ?

The inflection f(x)=2-ln(x^2+1) is (-1,2-ln(2)),(1,2-ln(2))

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inflection f(x)=2-ln(x^2+1)

inflection points

f (x) = 2 - ln (x^{2} + 1)

(- 1, 2 - ln (2)), (1, 2 - ln (2))

Solution steps

f^{''} (x) = - \frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Concave Upward

: - \infty < x < - 1,

Concave Downward

: - 1 < x < 1,

Concave Upward

: 1 < x < \infty

Plug

x = - 1

into

2 - ln (x^{2} + 1) : 2 - ln (2)

(- 1, 2 - ln (2))

Plug

x = 1

into

2 - ln (x^{2} + 1) : 2 - ln (2)

(1, 2 - ln (2))

(- 1, 2 - ln (2)), (1, 2 - ln (2))

f (x) = 5 - 3 x

f (x) = 3 x

f (x) = 4 x + 14

\frac{5 x}{x - 5}

y = \frac{1}{8} x + 2, (1, - 5)

What is the inflection f(x)=2-ln(x^2+1) ?
The inflection f(x)=2-ln(x^2+1) is (-1,2-ln(2)),(1,2-ln(2))