What is the perpendicular y= 1/8 x+2,(1,-5) ?

The perpendicular y= 1/8 x+2,(1,-5) is y=-8x+3

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perpendicular y= 1/8 x+2,(1,-5)

perpendicular

y = \frac{1}{8} x + 2, (1, - 5)

y = - 8 x + 3

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{8} x + 2

that passes through

(1, - 5)

Find the slope of

y = \frac{1}{8} x + 2 : m = \frac{1}{8}

Compute the slope of the perpendicular line:

m_{p} = - 8

Find the line with slope m=

- 8

and passing through

(1, - 5) : y = - 8 x + 3

y = - 8 x + 3

f (x) = \frac{2 x ^{2} + x - 18}{x ^{2} - 9}

f (x) = 1 - e^{- x^{2} \frac{1}{18}}

f (x) = cos (2 x) - 1

f (x) = \frac{x ^{2} - 9}{x ^{2} - 2 x - 1}

f (x) = x^{3} + 8 x^{2} + 16 x + 25

What is the perpendicular y= 1/8 x+2,(1,-5) ?
The perpendicular y= 1/8 x+2,(1,-5) is y=-8x+3