What is the asymptotes of f(x)=(17x^2)/(5x^2+6) ?

The asymptotes of f(x)=(17x^2)/(5x^2+6) is Horizontal: y= 17/5

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asymptotes of f(x)=(17x^2)/(5x^2+6)

asymptotes

f (x) = \frac{17 x ^{2}}{5 x ^{2} + 6}

Horizontal : y = \frac{17}{5}

Solution steps

Vertical asymptotes of

\frac{17 x ^{2}}{5 x ^{2} + 6} :

None

Horizontal Asymptotes of

\frac{17 x ^{2}}{5 x ^{2} + 6} : y = \frac{17}{5}

Slant Asymptotes of

\frac{17 x ^{2}}{5 x ^{2} + 6} :

None

Horizontal : y = \frac{17}{5}

f (x) = \frac{x ^{2} - 6 x}{x ^{4} - 1296}

Y (x) = - \frac{2}{3} x + 7, (3, 3)

f (x) = - 3 x

\frac{∣ x ^{2} + x + 1 ∣}{x ^{2} - 1}

f (x) = (x + 3)^{2}, x \leq - 3

What is the asymptotes of f(x)=(17x^2)/(5x^2+6) ?
The asymptotes of f(x)=(17x^2)/(5x^2+6) is Horizontal: y= 17/5