What is the critical f(x)=-2x^3-9x^2+24x+3 ?

The critical f(x)=-2x^3-9x^2+24x+3 is x=-4,x=1

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critical f(x)=-2x^3-9x^2+24x+3

critical points

f (x) = - 2 x^{3} - 9 x^{2} + 24 x + 3

x = - 4, x = 1

Solution steps

- 2 x^{3} - 9 x^{2} + 24 x + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 1

Identify critical points not in

f (x)

domain

Domain of

- 2 x^{3} - 9 x^{2} + 24 x + 3 : - \infty < x < \infty

All critical points are in domain

x = - 4, x = 1

f (x) = x^{2} + 4 x + 3

y = 8 x^{3}

f (x) = x^{2} + 4

\frac{4}{3} x^{3}

f (x) = \frac{1}{x ^{3}}

What is the critical f(x)=-2x^3-9x^2+24x+3 ?
The critical f(x)=-2x^3-9x^2+24x+3 is x=-4,x=1