What is the critical f(x)=x^2+10 ?

The critical f(x)=x^2+10 is x=0

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critical f(x)=x^2+10

critical points

f (x) = x^{2} + 10

x = 0

Solution steps

x^{2} + 10

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} + 10 : - \infty < x < \infty

All critical points are in domain

x = 0

(7.5) (3.2)

3 - 4 x

f (x) = \frac{( x ^{2} + 1 )}{( x - 1 )}

f (x) = - 10 csc (x)

f (x) = - x^{3}