What is the range of f(x)=(x-2)/(1-3x) ?

The range of f(x)=(x-2)/(1-3x) is f(x) -1/3

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range of f(x)=(x-2)/(1-3x)

range

f (x) = \frac{x - 2}{1 - 3 x}

f (x) < - \frac{1}{3} or f (x) > - \frac{1}{3}

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 2}{1 - 3 x}

Inverse of

\frac{x - 2}{1 - 3 x} : - \frac{- 2 - x}{1 + 3 x}

- \frac{- 2 - x}{1 + 3 x}

Find the domain of each inverse function

Domain of

- \frac{- 2 - x}{1 + 3 x} : x < - \frac{1}{3} or x > - \frac{1}{3}

Combine the intervals

f (x) < - \frac{1}{3} or f (x) > - \frac{1}{3}

sin (x + \frac{3 π}{2})

4 x^{2} + 2

\frac{3 x + 1}{x - 2}

f (x) = \frac{- x ^{6} + 6 x}{10}

\frac{5 x + 1}{x - 3}

What is the range of f(x)=(x-2)/(1-3x) ?
The range of f(x)=(x-2)/(1-3x) is f(x)<-1/3 \lor f(x)>-1/3