What is the domain of f(x)=(x^2-9)/(x+3) ?

The domain of f(x)=(x^2-9)/(x+3) is x -3

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domain of f(x)=(x^2-9)/(x+3)

domain

f (x) = \frac{x ^{2} - 9}{x + 3}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

\frac{1}{2} (x - 2)^{2} - 3

3 x^{5} + 5 x^{3} - 2 x

(0, 1), (4.5, 2)

x^{2} ln (\frac{x}{6})

f (x) = x^{2} - 8 x + 12

What is the domain of f(x)=(x^2-9)/(x+3) ?
The domain of f(x)=(x^2-9)/(x+3) is x<-3\lor x>-3