What is the midpoint (-8,2),(-8+4sqrt(3),6) ?

The midpoint (-8,2),(-8+4sqrt(3),6) is (2(sqrt(3)-4),4)

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midpoint (-8,2),(-8+4sqrt(3),6)

midpoint

(- 8, 2), (- 8 + 43, 6)

(2 (3 - 4), 4)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 8, 2), (x_{2}, y_{2}) = (- 8 + 43, 6)

= (\frac{- 8 + 4 3 - 8}{2}, \frac{6 + 2}{2})

Refine

= (2 (3 - 4), 4)

\frac{x ( 2 x ^{2} - 3 x + 1 )}{x ^{3} + 1}

y = x + 1

f (x) = \frac{x + 2}{x}

f (x) = arctan (ln (e^{t a n (x^{2})}))

What is the midpoint (-8,2),(-8+4sqrt(3),6) ?
The midpoint (-8,2),(-8+4sqrt(3),6) is (2(sqrt(3)-4),4)