What is the inverse of f(x)=(2x+1)/(3x-1) ?

The inverse of f(x)=(2x+1)/(3x-1) is (1+x)/(3x-2)

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inverse of f(x)=(2x+1)/(3x-1)

inverse

f (x) = \frac{2 x + 1}{3 x - 1}

\frac{1 + x}{3 x - 2}

Solution steps

y = \frac{2 x + 1}{3 x - 1}

Replace

x

with

y

x = \frac{2 y + 1}{3 y - 1}

Solve for

y, x = \frac{2 y + 1}{3 y - 1}

\frac{1 + x}{3 x - 2}

(- x^{2} + 4) (x + 1)

4 x - 5 y = 20

(- 3.1, - 2.8), (- 4.92, - 3.3)

f (x) = x^{3} + 3 x^{2} + 3 x + 2

f (x) = 2 x^{3} + 4 x

What is the inverse of f(x)=(2x+1)/(3x-1) ?
The inverse of f(x)=(2x+1)/(3x-1) is (1+x)/(3x-2)