What is the domain of f(x)=(x^2)/(3x-7) ?

The domain of f(x)=(x^2)/(3x-7) is x 7/3

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domain of f(x)=(x^2)/(3x-7)

domain

f (x) = \frac{x ^{2}}{3 x - 7}

x < \frac{7}{3} or x > \frac{7}{3}

Interval Notation

(- \infty, \frac{7}{3}) \cup (\frac{7}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{7}{3}

The function domain

x < \frac{7}{3} or x > \frac{7}{3}

f (x) = (x + 2)^{5} (x - 3)^{4}

(- 3.2) (6)

\frac{- 3 x}{x ^{2} - 1}

5 x + y = - 3

f (x) = 8 x^{\frac{1}{3}}

What is the domain of f(x)=(x^2)/(3x-7) ?
The domain of f(x)=(x^2)/(3x-7) is x< 7/3 \lor x> 7/3