What is the critical f(x)=x^4+16x^3+54x^2+2 ?

The critical f(x)=x^4+16x^3+54x^2+2 is x=-9,x=-3,x=0

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critical f(x)=x^4+16x^3+54x^2+2

critical points

f (x) = x^{4} + 16 x^{3} + 54 x^{2} + 2

x = - 9, x = - 3, x = 0

Solution steps

x^{4} + 16 x^{3} + 54 x^{2} + 2

Find where

f^{'} (x)

is equal to zero or undefined

x = - 9, x = - 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{4} + 16 x^{3} + 54 x^{2} + 2 : - \infty < x < \infty

All critical points are in domain

x = - 9, x = - 3, x = 0

x - 2 y = - 6

f (x) = 2 x^{2} + 4 x - 3

f (x) = \frac{t + 2}{t ^{2} + 5 t + 6}

f (x) = \frac{2 x}{x ^{2} + 4}

What is the critical f(x)=x^4+16x^3+54x^2+2 ?
The critical f(x)=x^4+16x^3+54x^2+2 is x=-9,x=-3,x=0