What is the amplitude of f(x)=4sin(2x-pi/6)+2 ?

The amplitude of f(x)=4sin(2x-pi/6)+2 is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

amplitude of f(x)=4sin(2x-pi/6)+2

amplitude

f (x) = 4 sin (2 x - \frac{π}{6}) + 2

4

Solution steps

f (x) = 4 sin (2 x - \frac{π}{6}) + 2, A = 4

Therefore, the amplitude |A| is

4

4

x^{2} - 3 x

f (x) = \frac{8 x + 3}{7 x + 9}

f (x) = \frac{( x - 10 ) ^{3}}{10} + 5

f (x) = \frac{1}{e ^{x} - 1}

g (t) = t 4 - t

What is the amplitude of f(x)=4sin(2x-pi/6)+2 ?
The amplitude of f(x)=4sin(2x-pi/6)+2 is 4