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Popular >

distance (-4,7),(-10,13)

Solution

distance

(- 4, 7), (- 10, 13)

Solution

62

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 4, 7)

and

(- 10, 13)

is

= (- 10 - (- 4))^{2} + (13 - 7)^{2}

Simplify

= 62

Popular Examples

extreme f(x)=x^2+2x-4 extreme points

f (x) = x^{2} + 2 x - 4

range of f(x)=e^{(-5x-1/5)}+5 range

f (x) = e^{(- 5 x - \frac{1}{5})} + 5

inverse of f(x)=log_{2}(x-1)+3 inverse

f (x) = lo g_{2} (x - 1) + 3

inverse of ((x+5))/((x+6))inverse

\frac{( x + 5 )}{( x + 6 )}

domain of sqrt(5x+10)domain

5 x + 10

Frequently Asked Questions (FAQ)

What is the distance (-4,7),(-10,13) ?
The distance (-4,7),(-10,13) is 6sqrt(2)