What is the critical f(x)=(4x)/(x^2+1) ?

The critical f(x)=(4x)/(x^2+1) is x=-1,x=1

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critical f(x)=(4x)/(x^2+1)

critical points

f (x) = \frac{4 x}{x ^{2} + 1}

x = - 1, x = 1

Solution steps

\frac{4 x}{x ^{2} + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{4 x}{x ^{2} + 1} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 1

f (x) = 2 (x + 3)^{3} + 1

f (x) = \frac{( x + 5 ) ( 4 x + 3 )}{x ^{2} - 4}

f (t) = 2 sin (t + 3) + 1

lo g_{5} (x - 3)

3 e^{- 2 x}

What is the critical f(x)=(4x)/(x^2+1) ?
The critical f(x)=(4x)/(x^2+1) is x=-1,x=1