What is the inverse of f(x)=(x-11)^2,x<= 11 ?

The inverse of f(x)=(x-11)^2,x<= 11 is sqrt(x)+11,-sqrt(x)+11

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inverse of f(x)=(x-11)^2,x<= 11

inverse

f (x) = (x - 11)^{2}, x \leq 11

x + 11, - x + 11

Solution steps

y = (x - 11)^{2}

Replace

x

with

y

x = (y - 11)^{2}

Solve for

y, x = (y - 11)^{2}

x + 11, - x + 11

f (x) = \frac{( 3 x + 1 )}{( x - 2 )}

f (x) = x^{3} - x^{2} + x - 1

x + 2 y = 2

π - 3 arcsin (2 x - 1)

y = - \frac{1}{3} x + 9

What is the inverse of f(x)=(x-11)^2,x<= 11 ?
The inverse of f(x)=(x-11)^2,x<= 11 is sqrt(x)+11,-sqrt(x)+11