What is the inverse of f(x)=x^2,[0,infinity ] ?

The inverse of f(x)=x^2,[0,infinity ] is sqrt(x),-sqrt(x)

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inverse of f(x)=x^2,[0,infinity ]

inverse

f (x) = x^{2}, [0, \infty]

x, - x

Solution steps

y = x^{2}

Replace

x

with

y

x = y^{2}

Solve for

y, x = y^{2}

x, - x

f (x) = \frac{2 x ^{3} + 3}{x ^{3} + 2}

f (x) = x^{5}

f (x) = \frac{4 x - 1}{5 x - 3}

\frac{x ^{5}}{x ^{2} - 1}

(- 5, - 2), (- 8, - 5)

What is the inverse of f(x)=x^2,[0,infinity ] ?
The inverse of f(x)=x^2,[0,infinity ] is sqrt(x),-sqrt(x)