What is the critical e^x*(x^2+4x+1) ?

The critical e^x*(x^2+4x+1) is x=-5,x=-1

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critical e^x*(x^2+4x+1)

critical points

e^{x} \cdot (x^{2} + 4 x + 1)

x = - 5, x = - 1

Solution steps

e^{x} (x^{2} + 4 x + 1)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 5, x = - 1

Identify critical points not in

f (x)

domain

Domain of

e^{x} \cdot (x^{2} + 4 x + 1) : - \infty < x < \infty

All critical points are in domain

x = - 5, x = - 1

y = \frac{5}{6} x - 6, (- 2, 4)

f (x) = \frac{1}{3 x + 6}

x^{3} - 27

f (x) = \frac{x + 1}{x - 5}

(- 2, 8), (4, 6)