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Popular >

distance (2,-2),(-4,4)

Solution

distance

(2, - 2), (- 4, 4)

Solution

62

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, - 2)

and

(- 4, 4)

is

= (- 4 - 2)^{2} + (4 - (- 2))^{2}

Simplify

= 62

Popular Examples

perpendicular y= 4/3 x+6,(-4,-1)perpendicular

y = \frac{4}{3} x + 6, (- 4, - 1)

domain of f(x)=(x^2-3x-4)/(x-4)domain

f (x) = \frac{x ^{2} - 3 x - 4}{x - 4}

symmetry x^3+2x^2-x-2 symmetry

x^{3} + 2 x^{2} - x - 2

domain of f(x)=sqrt(x^2-49)domain

f (x) = x^{2} - 49

domain of (1/(x-4))(1/(6-x))domain

(\frac{1}{x - 4}) (\frac{1}{6 - x})

Frequently Asked Questions (FAQ)

What is the distance (2,-2),(-4,4) ?
The distance (2,-2),(-4,4) is 6sqrt(2)