What is x^2+14x+y^2+10y+62=0 ?

The solution to x^2+14x+y^2+10y+62=0 is Circle with (a,b)=(-7,-5),r=2sqrt(3)

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x^2+14x+y^2+10y+62=0

x^{2} + 14 x + y^{2} + 10 y + 62 = 0

(a, b) = (- 7, - 5), r = 23

Solution steps

x^{2} + 14 x + y^{2} + 10 y + 62 = 0

Rewrite

x^{2} + 14 x + y^{2} + 10 y + 62 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 5))^{2} = (23)^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 5), r = 23

(x + 1)^{2} + (y - 3)^{2} = 3

x^{2} + y^{2} - 2 x - 6 y + 7 = 0

(x + 5)^{2} + (y + 8)^{2} = 81

2 x^{2} + 2 y^{2} = 16

(x - 4)^{2} + (y - 1)^{2} = 25

What is x^2+14x+y^2+10y+62=0 ?
The solution to x^2+14x+y^2+10y+62=0 is Circle with (a,b)=(-7,-5),r=2sqrt(3)