What is 3x^2+3y^2+24x-12y=0 ?

The solution to 3x^2+3y^2+24x-12y=0 is Circle with (a,b)=(-4,2),r=2sqrt(5)

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3x^2+3y^2+24x-12y=0

3 x^{2} + 3 y^{2} + 24 x - 12 y = 0

(a, b) = (- 4, 2), r = 25

Solution steps

3 x^{2} + 3 y^{2} + 24 x - 12 y = 0

Rewrite

3 x^{2} + 3 y^{2} + 24 x - 12 y = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 2)^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 2), r = 25

(x + 4)^{2} + (y + 4)^{2} = 9

x^{2} + y^{2} + 2 x + 6 y = 0

x^{2} - 4 x + y^{2} + 6 y + 12 = 0

50 = 30 - 13 x + 5 y + \frac{x ^{2}}{2} + \frac{y ^{2}}{2}

x^{2} + y^{2} = 10 - x^{2} - y^{2}

What is 3x^2+3y^2+24x-12y=0 ?
The solution to 3x^2+3y^2+24x-12y=0 is Circle with (a,b)=(-4,2),r=2sqrt(5)