What is x^2+y^2-3x+5y-14=0 ?

The solution to x^2+y^2-3x+5y-14=0 is Circle with (a,b)=(3/2 ,-5/2),r=(3sqrt(5))/(sqrt(2))

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x^2+y^2-3x+5y-14=0

x^{2} + y^{2} - 3 x + 5 y - 14 = 0

(a, b) = (\frac{3}{2}, - \frac{5}{2}), r = \frac{3 5}{2}

Solution steps

x^{2} + y^{2} - 3 x + 5 y - 14 = 0

Rewrite

x^{2} + y^{2} - 3 x + 5 y - 14 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- \frac{5}{2}))^{2} = (\frac{3 5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - \frac{5}{2}), r = \frac{3 5}{2}

(x + 3)^{2} + (y - 4)^{2} = 9

(x - 6)^{2} + (y - 4)^{2} = 64

x^{2} + y^{2} - 12 x + 6 y + 36 = 0

4 y^{2} + 4 x^{2} - 24 x + 35 = 0

x^{2} + y^{2} + 10 x + 14 y = - 70

What is x^2+y^2-3x+5y-14=0 ?
The solution to x^2+y^2-3x+5y-14=0 is Circle with (a,b)=(3/2 ,-5/2),r=(3sqrt(5))/(sqrt(2))