What is 3(x+3/4)^2+3(y-1/2)^2=36 ?

The solution to 3(x+3/4)^2+3(y-1/2)^2=36 is Circle with (a,b)=(-3/4 , 1/2),r=2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3(x+3/4)^2+3(y-1/2)^2=36

3 (x + \frac{3}{4})^{2} + 3 (y - \frac{1}{2})^{2} = 36

(a, b) = (- \frac{3}{4}, \frac{1}{2}), r = 23

Solution steps

3 (x + \frac{3}{4})^{2} + 3 (y - \frac{1}{2})^{2} = 36

Rewrite

3 (x + \frac{3}{4})^{2} + 3 (y - \frac{1}{2})^{2} = 36

in the form of the standard circle equation

(x - (- \frac{3}{4}))^{2} + (y - \frac{1}{2})^{2} = (23)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{4}, \frac{1}{2}), r = 23

x^{2} + y^{2} + 12 x + 4 y + 15 = 0

(x - 10)^{2} + (y + 8)^{2} = 36

x^{2} + y^{2} - 4 > 0

y^{2} + x^{2} = 10

(x - 6)^{2} + (y - 2)^{2} = 9

What is 3(x+3/4)^2+3(y-1/2)^2=36 ?
The solution to 3(x+3/4)^2+3(y-1/2)^2=36 is Circle with (a,b)=(-3/4 , 1/2),r=2sqrt(3)