What is (x-6)^2+(y-5)^2=49 ?

The solution to (x-6)^2+(y-5)^2=49 is Circle with (a,b)=(6,5),r=7

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(x-6)^2+(y-5)^2=49

(x - 6)^{2} + (y - 5)^{2} = 49

(a, b) = (6, 5), r = 7

Solution steps

(x - 6)^{2} + (y - 5)^{2} = 49

Rewrite

(x - 6)^{2} + (y - 5)^{2} = 49

in the form of the standard circle equation

(x - 6)^{2} + (y - 5)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (6, 5), r = 7

x^{2} + y^{2} + 14 x - 2 = - 1

(x - 5)^{2} + (y + 3)^{2} = 25

4 x^{2} + 4 y^{2} - 20 x + 40 y + 5 = 0

x^{2} + y^{2} - 6 x - 8 y + 16 = 0

x^{2} + y^{2} + 10 x - 18 y + 70 = 0

What is (x-6)^2+(y-5)^2=49 ?
The solution to (x-6)^2+(y-5)^2=49 is Circle with (a,b)=(6,5),r=7