What is x^2+y^2+6x-22y+120=0 ?

The solution to x^2+y^2+6x-22y+120=0 is Circle with (a,b)=(-3,11),r=sqrt(10)

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x^2+y^2+6x-22y+120=0

x^{2} + y^{2} + 6 x - 22 y + 120 = 0

(a, b) = (- 3, 11), r = 10

Solution steps

x^{2} + y^{2} + 6 x - 22 y + 120 = 0

Rewrite

x^{2} + y^{2} + 6 x - 22 y + 120 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 11)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 11), r = 10

(x + 4)^{2} + (y + 5)^{2} = 36

(x - 6)^{2} + (y - 7)^{2} = 8^{2}

(x - 3)^{2} + (y - 2)^{2} = 5

(x - 3)^{2} + (y - 2)^{2} = 2

x^{2} + y^{2} - 4 x - 12 y - 23 = 0

What is x^2+y^2+6x-22y+120=0 ?
The solution to x^2+y^2+6x-22y+120=0 is Circle with (a,b)=(-3,11),r=sqrt(10)