What is x^2+y^2-2x-4y+2=0 ?

The solution to x^2+y^2-2x-4y+2=0 is Circle with (a,b)=(1,2),r=sqrt(3)

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x^2+y^2-2x-4y+2=0

x^{2} + y^{2} - 2 x - 4 y + 2 = 0

(a, b) = (1, 2), r = 3

Solution steps

x^{2} + y^{2} - 2 x - 4 y + 2 = 0

Rewrite

x^{2} + y^{2} - 2 x - 4 y + 2 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 3

x^{2} + y^{2} - 26 x + 165 = 0

(x + 4)^{2} + (y + 6)^{2} = 16

(x - 8)^{2} + (y + 2)^{2} = 4

(x + 2)^{2} + (y + 5)^{2} = 1 2^{2}

(x - 4)^{2} + (y - 3)^{2} = 4^{2}

What is x^2+y^2-2x-4y+2=0 ?
The solution to x^2+y^2-2x-4y+2=0 is Circle with (a,b)=(1,2),r=sqrt(3)