What is (x+4)^2+(y+6)^2=16 ?

The solution to (x+4)^2+(y+6)^2=16 is Circle with (a,b)=(-4,-6),r=4

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(x+4)^2+(y+6)^2=16

(x + 4)^{2} + (y + 6)^{2} = 16

(a, b) = (- 4, - 6), r = 4

Solution steps

(x + 4)^{2} + (y + 6)^{2} = 16

Rewrite

(x + 4)^{2} + (y + 6)^{2} = 16

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 6))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 6), r = 4

(x - 8)^{2} + (y + 2)^{2} = 4

(x + 2)^{2} + (y + 5)^{2} = 1 2^{2}

(x - 4)^{2} + (y - 3)^{2} = 4^{2}

(x + 4)^{2} + (y + 6)^{2} = 49

x^{2} + y^{2} - 8 x + 2 y - 8 = 0

What is (x+4)^2+(y+6)^2=16 ?
The solution to (x+4)^2+(y+6)^2=16 is Circle with (a,b)=(-4,-6),r=4