What is (x+4)^2+(y+6)^2=49 ?

The solution to (x+4)^2+(y+6)^2=49 is Circle with (a,b)=(-4,-6),r=7

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(x+4)^2+(y+6)^2=49

(x + 4)^{2} + (y + 6)^{2} = 49

(a, b) = (- 4, - 6), r = 7

Solution steps

(x + 4)^{2} + (y + 6)^{2} = 49

Rewrite

(x + 4)^{2} + (y + 6)^{2} = 49

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 6))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 6), r = 7

x^{2} + y^{2} - 8 x + 2 y - 8 = 0

9 x^{2} - 42 x + 9 y^{2} + 84 y + 65 = 0

{x - (- 3)}^{2} + {y - (- 4)}^{2} = 1

(x - 5)^{2} + (y + 2)^{2} = 7.5

x^{2} + (y - 7.5)^{2} = \frac{9}{49}

What is (x+4)^2+(y+6)^2=49 ?
The solution to (x+4)^2+(y+6)^2=49 is Circle with (a,b)=(-4,-6),r=7