What is 4x^2+20x+4y^2-24y+21=0 ?

The solution to 4x^2+20x+4y^2-24y+21=0 is Circle with (a,b)=(-5/2 ,3),r=sqrt(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+20x+4y^2-24y+21=0

4 x^{2} + 20 x + 4 y^{2} - 24 y + 21 = 0

(a, b) = (- \frac{5}{2}, 3), r = 10

Solution steps

4 x^{2} + 20 x + 4 y^{2} - 24 y + 21 = 0

Rewrite

4 x^{2} + 20 x + 4 y^{2} - 24 y + 21 = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - 3)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, 3), r = 10

(x + \frac{8}{3})^{2} + y^{2} = 1

x^{2} + y^{2} - 6 x - 8 y - 24 = 0

(x - 1)^{2} + (y - 1)^{2} = 3^{2}

y^{2} - 4 y + x^{2} - 6 x - 12 = 0

2 x^{2} + 2 y^{2} - 10 x - 18 y = 1

What is 4x^2+20x+4y^2-24y+21=0 ?
The solution to 4x^2+20x+4y^2-24y+21=0 is Circle with (a,b)=(-5/2 ,3),r=sqrt(10)