What is 2x^2+2y^2-10x-18y=1 ?

The solution to 2x^2+2y^2-10x-18y=1 is Circle with (a,b)=(5/2 , 9/2),r=3sqrt(3)

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2x^2+2y^2-10x-18y=1

2 x^{2} + 2 y^{2} - 10 x - 18 y = 1

(a, b) = (\frac{5}{2}, \frac{9}{2}), r = 33

Solution steps

2 x^{2} + 2 y^{2} - 10 x - 18 y = 1

Rewrite

2 x^{2} + 2 y^{2} - 10 x - 18 y = 1

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - \frac{9}{2})^{2} = (33)^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, \frac{9}{2}), r = 33

a^{2} + b^{2} = a + b

1 - x^{2} - y^{2} > 0

25^{2} = (x - 0)^{2} + (y - (- 0))^{2}

x^{2} + y^{2} - 14 x - 8 y + 1 = 0

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

What is 2x^2+2y^2-10x-18y=1 ?
The solution to 2x^2+2y^2-10x-18y=1 is Circle with (a,b)=(5/2 , 9/2),r=3sqrt(3)