What is x^2+y^2-14x-8y+1=0 ?

The solution to x^2+y^2-14x-8y+1=0 is Circle with (a,b)=(7,4),r=8

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x^2+y^2-14x-8y+1=0

x^{2} + y^{2} - 14 x - 8 y + 1 = 0

(a, b) = (7, 4), r = 8

Solution steps

x^{2} + y^{2} - 14 x - 8 y + 1 = 0

Rewrite

x^{2} + y^{2} - 14 x - 8 y + 1 = 0

in the form of the standard circle equation

(x - 7)^{2} + (y - 4)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (7, 4), r = 8

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

x^{2} - 2 x + y^{2} - 4 y = 4

x^{2} + y^{2} + 14 x - 8 y + 16 = 0

- 21 x - 42.4 = (x - 0)^{2} + (y - 1.6)^{2} - 2. 1^{2}

x^{2} + 6 x + y^{2} - 8 y = 56

What is x^2+y^2-14x-8y+1=0 ?
The solution to x^2+y^2-14x-8y+1=0 is Circle with (a,b)=(7,4),r=8