What is x^2+y^2+14x-8y+16=0 ?

The solution to x^2+y^2+14x-8y+16=0 is Circle with (a,b)=(-7,4),r=7

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x^2+y^2+14x-8y+16=0

x^{2} + y^{2} + 14 x - 8 y + 16 = 0

(a, b) = (- 7, 4), r = 7

Solution steps

x^{2} + y^{2} + 14 x - 8 y + 16 = 0

Rewrite

x^{2} + y^{2} + 14 x - 8 y + 16 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 4)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, 4), r = 7

- 21 x - 42.4 = (x - 0)^{2} + (y - 1.6)^{2} - 2. 1^{2}

x^{2} + 6 x + y^{2} - 8 y = 56

x^{2} + y^{2} - 14 x + 12 y + 49 = 0

(x + 2)^{2} + (y + 5)^{2} = 9

(x + \frac{7}{2})^{2} + (y - \frac{5}{2})^{2} = \frac{125}{2}

What is x^2+y^2+14x-8y+16=0 ?
The solution to x^2+y^2+14x-8y+16=0 is Circle with (a,b)=(-7,4),r=7