What is -21x-42.4=(x-0)^2+(y-1.6)^2-2.1^2 ?

The solution to -21x-42.4=(x-0)^2+(y-1.6)^2-2.1^2 is Circle with (a,b)=(-21/2 ,1.6),r=8.50058…

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-21x-42.4=(x-0)^2+(y-1.6)^2-2.1^2

- 21 x - 42.4 = (x - 0)^{2} + (y - 1.6)^{2} - 2. 1^{2}

(a, b) = (- \frac{21}{2}, 1.6), r = 8.50058 \dots

Solution steps

- 21 x - 42.4 = (x - 0)^{2} + (y - 1.6)^{2} - 2. 1^{2}

Rewrite

- 21 x - 42.4 = (x - 0)^{2} + (y - 1.6)^{2} - 2. 1^{2}

in the form of the standard circle equation

(x - (- \frac{21}{2}))^{2} + (y - 1.6)^{2} = 8.50058 \dots^{2}

Therefore the circle properties are:

(a, b) = (- \frac{21}{2}, 1.6), r = 8.50058 \dots

x^{2} + 6 x + y^{2} - 8 y = 56

x^{2} + y^{2} - 14 x + 12 y + 49 = 0

(x + 2)^{2} + (y + 5)^{2} = 9

(x + \frac{7}{2})^{2} + (y - \frac{5}{2})^{2} = \frac{125}{2}

x^{2} + (y - 5)^{2} = 4

What is -21x-42.4=(x-0)^2+(y-1.6)^2-2.1^2 ?
The solution to -21x-42.4=(x-0)^2+(y-1.6)^2-2.1^2 is Circle with (a,b)=(-21/2 ,1.6),r=8.50058…