What is (x-3)^2+(y-4)^2=5^2 ?

The solution to (x-3)^2+(y-4)^2=5^2 is Circle with (a,b)=(3,4),r=5

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(x-3)^2+(y-4)^2=5^2

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

(a, b) = (3, 4), r = 5

Solution steps

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

Rewrite

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

in the form of the standard circle equation

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (3, 4), r = 5

x^{2} - 2 x + y^{2} - 4 y = 4

x^{2} + y^{2} + 14 x - 8 y + 16 = 0

- 21 x - 42.4 = (x - 0)^{2} + (y - 1.6)^{2} - 2. 1^{2}

x^{2} + 6 x + y^{2} - 8 y = 56

x^{2} + y^{2} - 14 x + 12 y + 49 = 0

What is (x-3)^2+(y-4)^2=5^2 ?
The solution to (x-3)^2+(y-4)^2=5^2 is Circle with (a,b)=(3,4),r=5