What is 1-x^2-y^2>0 ?

The solution to 1-x^2-y^2>0 is Circle with (a,b)=(0,0),r=1

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1-x^2-y^2>0

1 - x^{2} - y^{2} > 0

(a, b) = (0, 0), r = 1

Solution steps

1 - x^{2} - y^{2} > 0

Rewrite

1 - x^{2} - y^{2} > 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

25^{2} = (x - 0)^{2} + (y - (- 0))^{2}

x^{2} + y^{2} - 14 x - 8 y + 1 = 0

(x - 3)^{2} + (y - 4)^{2} = 5^{2}

x^{2} - 2 x + y^{2} - 4 y = 4

x^{2} + y^{2} + 14 x - 8 y + 16 = 0

What is 1-x^2-y^2>0 ?
The solution to 1-x^2-y^2>0 is Circle with (a,b)=(0,0),r=1