What is (x/2)^2+(y/2)^2=35^2 ?

The solution to (x/2)^2+(y/2)^2=35^2 is Circle with (a,b)=(0,0),r=70

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(x/2)^2+(y/2)^2=35^2

(\frac{x}{2})^{2} + (\frac{y}{2})^{2} = 3 5^{2}

(a, b) = (0, 0), r = 70

Solution steps

(\frac{x}{2})^{2} + (\frac{y}{2})^{2} = 3 5^{2}

Rewrite

(\frac{x}{2})^{2} + (\frac{y}{2})^{2} = 3 5^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 7 0^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 70

x^{2} + y^{2} < 100

(x - 2)^{2} + (y + 1)^{2} = 5

(x - 2)^{2} + (y + 1)^{2} = 3^{2}

x^{2} + y^{2} - 4 x - 6 y - 11 = 0

x^{2} + y^{2} = 402

What is (x/2)^2+(y/2)^2=35^2 ?
The solution to (x/2)^2+(y/2)^2=35^2 is Circle with (a,b)=(0,0),r=70