What is (x-2)^2+(y+1)^2=3^2 ?

The solution to (x-2)^2+(y+1)^2=3^2 is Circle with (a,b)=(2,-1),r=3

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(x-2)^2+(y+1)^2=3^2

(x - 2)^{2} + (y + 1)^{2} = 3^{2}

(a, b) = (2, - 1), r = 3

Solution steps

(x - 2)^{2} + (y + 1)^{2} = 3^{2}

Rewrite

(x - 2)^{2} + (y + 1)^{2} = 3^{2}

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, - 1), r = 3

x^{2} + y^{2} - 4 x - 6 y - 11 = 0

x^{2} + y^{2} = 402

x^{2} + y^{2} + 14 y + 45 = 0

3 x^{2} + 3 y^{2} - 12 x + 18 y = 9

x^{2} + y (y + 4) = 10 x + 7

What is (x-2)^2+(y+1)^2=3^2 ?
The solution to (x-2)^2+(y+1)^2=3^2 is Circle with (a,b)=(2,-1),r=3