What is x^2+y(y+4)=10x+7 ?

The solution to x^2+y(y+4)=10x+7 is Circle with (a,b)=(5,-2),r=6

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x^2+y(y+4)=10x+7

x^{2} + y (y + 4) = 10 x + 7

(a, b) = (5, - 2), r = 6

Solution steps

x^{2} + y (y + 4) = 10 x + 7

Rewrite

x^{2} + y (y + 4) = 10 x + 7

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 6

x^{2} + y^{2} + 4 x - 4 y = 21

x^{2} + y^{2} = 23

x^{2} - 10 x + y^{2} = - 9

4 (x - 3)^{2} + 4 y^{2} = 16

4 x^{2} + 4 y^{2} - 8 y - 5 = 0

What is x^2+y(y+4)=10x+7 ?
The solution to x^2+y(y+4)=10x+7 is Circle with (a,b)=(5,-2),r=6