What is 4(x-3)^2+4y^2=16 ?

The solution to 4(x-3)^2+4y^2=16 is Circle with (a,b)=(3,0),r=2

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4(x-3)^2+4y^2=16

4 (x - 3)^{2} + 4 y^{2} = 16

(a, b) = (3, 0), r = 2

Solution steps

4 (x - 3)^{2} + 4 y^{2} = 16

Rewrite

4 (x - 3)^{2} + 4 y^{2} = 16

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 2

4 x^{2} + 4 y^{2} - 8 y - 5 = 0

(x - 1)^{2} + (y - 3)^{2} = 49

(x + 1)^{2} + (y - 2)^{2} = 49

x^{2} + y^{2} - 6 x + 6 y + 10 = 0

x^{2} + y^{2} - 2 x - 6 y + 9 = 0

What is 4(x-3)^2+4y^2=16 ?
The solution to 4(x-3)^2+4y^2=16 is Circle with (a,b)=(3,0),r=2